I think the best amount to allocate to stack size is a power of 2. For example:
If we take 64 (2^6) for the amount, you can divide the stack like this:
1*64, 2*32, 4*16, 32 + 2*16, 8*8, 64*1,etc...
If we use a little divisible size, we will find constant problems in the distribution.